Casio Land Survey Program

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This is a collection of programs I wrote on the Casio fx-5800p. These programs should also work on any Casio Graphing calculator (fx-9860g, fx-9750g, Prizm) since the programming language between Casio calculators remains largely the same.Now if I can find my fx-5800p that I misplaced last night.

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  3. Casio Land Survey Program For Windows 10

Thank goodness for notes!Notes for the fx-5800p programs:There are no SIGN or MOD functions. Here are the work arounds I used (see SUN):SIGN(x).X 0 ⇒ 1 → X-X 0 ⇒ -1 → X.n MOD d.N - D Intg( N ÷ D ) → result variable.Table of Contents:1. Rotation of (x, y) (ROTATEXY)2. Law of Cosines (COSINES)3.

Pendulum: Period and Average Velocity (PENDULUM)4. Arc Length of a Parabola (QUADLENGTH)5.

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Position of the Sun (SUN)1. Fx-5800p: ROTATEXYRotates the coordinate (X, Y).

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The direction of rotation follows the conventional direction (counterclockwise). The variable A represents the angle (θ).Program:'X'? → A X, Y × cos(A), sin(A) -sin(A), cos(A) 2. Fx-5800p: COSINESSides: D, E, FCorresponding Angles: A, B, CProgram:Lbl 0Cls'KNOWN:'1. A,E,F'?→II = 1 ⇒ Goto 1I = 2 ⇒ Goto 2Goto 0Lbl 1'D'? → F'A': cos ⁻¹ (( E ² + F ² - D ² ) ÷ ( 2EF )) → A ◢'B': cos ⁻¹ (( D ² + F ² - E ² ) ÷ ( 2DF )) → B ◢'C': 180° - A - BStopLbl 2'A'? → F:'D': √ (E ² + F ² - 2 E F cos A ) → D ◢'B': cos ⁻¹ ( ( D ² + F ² - E ² ) ÷ (2DF)) → B ◢'C': 180° - A - B3.

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Fx-5800p: PENDULUMVariables:D = length of the step or bar holding the pendulumL = length of the rod or string that is swingingR = large radius of the circular ringAt the units, enter 0 for US units (set g = 32.174 ft/s^2), anything else for SI units (g = 9.80665 m/s^2).Calculated:T = period of the pendulum (the amount of time it takes for the pendulum from one end to the other)V = average velocity of the pendulum (once in its in full swing)Program:Cls'=0 U.S.' → GIf G = 0Then 32.174 → GElse g → G IfEnd // g from the constant menu (9.80665)Lbl 0Cls'1. RING'?→ II = 1 ⇒ Goto 1I = 2 ⇒ Goto 2I = 3 ⇒ Goto 3Goto 0Lbl 1'D'? → L2 π √( L ÷ 3G ) → T: Goto 4Lbl 2'D'?

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→ L2 π √(L ÷ G) → T: Goto 4Lbl 3'D'? → R2 π √( R ² ÷ GL → T: Goto 4Lbl 4'T =': T ◢ 'V =': D ÷ T → V-Test Examples:Rod: D = 1 m, L = 1.6 m. Results: T = 6 sec, V =.

M/sString: D = 2 m, L = 1.75 m. Results: T = 2.65423008 sec, V =.5 m/sCircular Ring: D = 2 ft, L = 2 ft, r = 1.2 ftResults: T = 1.879851674 sec, V = 1.063913727 m/s4.

Fx-5800p: QUADLENGTHFind the length of a parabola given height and width and a corresponding equation:f(x) = Ax^2 + BxWhereA = -4h/l^2B = 4h/lProgram:Cls'LENGTH'? → HCls'COEF OF X ²'-4 H ÷ L ² ◢'COEF OF X'4 H ÷ L ◢'ARC LENGTH'∫ ( √ ( 1 + ( -8 H X ÷ L ² + 4 H ÷ L ) ), 0, L)Test Data:L: 16.4, H: 8.2X^2 coefficient:.X coefficient: 25. Fx-5800P: SUNSource for the formulas:Gives the RA (right ascension) and δ (declination) of the sun at any date. U is the universal time, the time it would be at Greenwich Village (Int'l Date Line).For the Pacific Time Zone:Standard Time: PST + 8 hours = UTDaylight Savings Time: PDT + 7 hours = UTProgram:'MONTH'?

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→ UDeg100 Y + M - 190002.5 → XX 0 ⇒ 1 → X-X 0 ⇒ -1 → X367 Y - Intg( 7 ( Y + Intg( ( M + 9 ) ÷ 12 ) ) ÷ 4 )+ Intg( 275 M ÷ 9 ) + D + 1721013.5 + U ÷ 24-.5 X +.5 → DD - 2451545 → D357.529 +.98560028 D → GG - 360 Intg( G ÷ 360 ) → G280.459 +.98564736 D → QQ - 360 Intg( Q ÷ 360 ) → QQ + 1.915 sin( G ) +.02 sin( 2G ) → LL - 360 Intg( L ÷ 360 ) → L1.00014 -.01671 cos( G ) -.00014 cos( 2 G ) → R23.439 -.00000036 D → Etan ⁻¹ (cos(E) tan(L)) → AIf L ≥ 90 And L.